This question tests inverse proportion using printing speed and time.
This question tests your understanding of inverse proportion using printing speed and time. At Higher GCSE level, inverse proportion questions often involve rates rather than simple counts of workers or machines. Being confident with rates such as “pages per minute” is essential.
In this problem, the constant quantity is the total number of pages printed. Whether the printer works slowly or quickly, the total output remains the same. This means:
printing speed × time = total pages
If the printing speed increases, the time required must decrease for the same number of pages. This opposite movement is what defines inverse proportion.
Speed tells us how much work is done per unit of time. When speed is multiplied by a factor, the time taken is divided by the same factor, provided the total amount of work does not change.
This approach avoids confusion and keeps the working clear for examiners.
Example: A printer produces 80 pages in 16 minutes. How long would it take to print 200 pages if the speed doubles?
Doubling the speed halves the time needed per page.
Example: A copier prints 150 pages in 30 minutes. How long would it take to print 300 pages at the same speed?
This example shows that if the speed does not change, time is directly proportional to the number of pages.
Understanding inverse proportion with rates is useful in offices, factories, and digital systems. Faster machines reduce waiting time, while slower speeds increase it. This logic also applies to data transfer rates and download times.
Whenever you see phrases like “double speed”, “triple speed”, or “half speed”, immediately think inverse proportion and work with rates.
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