This question tests inverse proportion using speed and time for a fixed distance.
This question tests your understanding of inverse proportion using speed and time, a key Higher GCSE Maths topic. When travelling the same distance, speed and time are inversely proportional: increasing the speed reduces the time taken, while decreasing the speed increases the time taken.
In speed problems like this one, the quantity that stays constant is the distance travelled. This leads to the core relationship:
speed × time = distance
If the distance does not change, the product of speed and time must remain the same.
If the cyclist travels faster, each hour covers more distance. As a result, fewer hours are needed to complete the same journey. This opposite movement of the two variables is what defines inverse proportion.
This structured approach is especially important in Higher-tier questions, where decimals and unfamiliar speeds are common.
Example: A runner completes a route in 2.5 hours at 12 km/h. How long would the same route take at 20 km/h?
Increasing the speed reduces the time taken.
Example: A car travels a fixed distance in 1.2 hours at 75 km/h. How long would it take at 60 km/h?
Reducing the speed increases the travel time.
Inverse proportion between speed and time is used in journey planning, logistics, and sports performance. Understanding this relationship helps estimate arrival times and compare travel options accurately.
When a question mentions the same distance or same route, immediately write down speed × time = constant. This helps you avoid choosing a direct proportion method by mistake.
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