This Higher GCSE question involves multiplying fractional scale factors — a key skill for compound changes in geometry, ratio, and proportional reasoning. The total effect of two fractional reductions is found by multiplying the fractions together.
When fractional changes happen successively, multiply the fractions — not add them — to find the overall change. Simplify to make the result clear.
In GCSE Maths, multiplying fractions isn’t only a numerical exercise — it models compound effects. When two scale factors, proportions, or fractional changes are applied one after another, the total change is found by multiplying the fractions together.
A designer makes a scale model of a car that is \( \tfrac{2}{3} \) of the real car’s length. Later, the model is digitally reduced again to \( \tfrac{3}{5} \) of its current size for an animation. To find the overall scale factor compared with the real car, multiply the two reductions:
\[ \tfrac{2}{3} \times \tfrac{3}{5} = \tfrac{6}{15} = \tfrac{2}{5}. \]
So the animated version is \( \tfrac{2}{5} \) of the real car’s size. This compound use of fractions is common when working with models, enlargements, or successive percentage changes.
Example 1 – Area scaling:
A diagram is reduced to \( \tfrac{4}{5} \) of its original side length. The new area is \( \tfrac{4}{5} \times \tfrac{4}{5} = \tfrac{16}{25} \) of the original.
Example 2 – Recipe scaling:
A recipe uses \( \tfrac{3}{4} \) of the original ingredients to make a smaller batch. Then only \( \tfrac{2}{3} \) of that smaller batch is served. Fraction of the original ingredients actually used: \( \tfrac{3}{4} \times \tfrac{2}{3} = \tfrac{6}{12} = \tfrac{1}{2}. \)
Example 3 – Volume scaling:
If each linear dimension of a cube is multiplied by \( \tfrac{3}{5} \), the new volume fraction is \( \tfrac{3}{5} \times \tfrac{3}{5} \times \tfrac{3}{5} = \tfrac{27}{125} \). Compound multiplication shows how volumes shrink faster than lengths.
Understanding fractional scaling prepares you for algebraic and geometric reasoning in Higher Maths. It explains why areas and volumes change faster than lengths, and how repeated fractional changes (discounts, dilutions, depreciation) combine through multiplication, not addition.
When you see the word “of” in a problem (for example, “\( \tfrac{3}{4} \) of \( \tfrac{2}{5} \)”), replace it with multiplication. This helps translate language into maths quickly.