This Higher-tier decimals question builds accuracy and confidence when multiplying decimals of different lengths. Understanding place value and estimation is key.
Estimate before multiplying: 0.7×2≈1.4, so an answer around 1.5 is expected. Use this to check decimal placement.
This Higher-tier decimals problem reinforces precision in multiplying numbers with different decimal lengths. Students must recognise how decimal placement and estimation interact to verify reasonableness.
When multiplying decimals, the total number of decimal places in the product equals the sum of the decimal places in both factors. Estimation provides a quick mental check that the decimal point is correctly positioned.
Estimate before calculating: 0.68 is roughly two-thirds, and 2.25 ≈ 2. Multiplying gives ≈1.3–1.4. The exact result 1.53 is close, confirming correct placement of the decimal.
Apply the same principle to find \(0.684\times2.25\), or \(0.68\times2.254\), rounding to 3 significant figures. This variation introduces more digits while preserving place-value reasoning.
0.68 ≈ \(\tfrac{17}{25}\), 2.25 = \(\tfrac{9}{4}\). Multiply fractions: \(\tfrac{17}{25}\times\tfrac{9}{4}=\tfrac{153}{100}=1.53.\) The fractional form confirms the decimal result exactly.
Always align your expectations before calculating. A result near 1.5 makes sense here because multiplying by 2.25 should roughly double 0.68, with a small additional increase. Checking by estimation guards against misplaced decimals and reinforces conceptual understanding of magnitude.
Mastering multi-decimal multiplication is crucial for GCSE success in percentage growth, compound interest, and unit conversion problems where precision and estimation meet.