This is a two-step probability question without replacement. Use a tree diagram and multiply the probabilities along the correct path.
Use P(Red then Red) = P(First Red) × P(Second Red | First Red). Update the totals after the first draw.
In GCSE Maths, tree diagrams are a clear way to organise two-step probability problems. They are especially useful when events are dependent, meaning the result of the first step affects the probabilities in the second step. This happens whenever you draw an item without replacement (you do not put it back).
At the start, you calculate the first probability using:
favourable outcomes ÷ total outcomes
After the first draw, the total number of items usually decreases by 1. If the first draw removed an item of the colour you care about, the number of favourable outcomes also decreases by 1. That is why the second probability is written as a conditional probability (for example, “second red given that the first was red”).
A bag has 4 red balls and 1 green ball. Two balls are drawn without replacement. Find the probability that both are red.
A frequent mistake is to assume the second probability stays the same as the first. For example, with 6 blue and 4 yellow (10 total), some students write P(two blues) as (6/10) × (6/10). This is incorrect because after taking a blue, there are only 5 blues left out of 9. Always reduce the total by 1 for the second draw when there is no replacement.
This idea appears in card games (drawing two hearts), quality checks (testing two items from a batch), and simple experiments (selecting two people from a group). Whenever you choose items one after another and don’t return them, you are using dependent probability.
Study tip: When you see “without replacement”, immediately think: “second fraction uses a denominator one smaller.”
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