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GCSE Maths Practice: simultaneous-equations

Question 11 of 15

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\( \text{Solve: } 3x + 5y = 14, 4x - y = 10 \)

Choose one option:

\( x = 64/23, y = 26/23 \) \( x = 3, y = 2 \) \( x = 4, y = 1 \)

\( \text{Substitute y = 4x - 10 into 3x + 5y = 14, solve for x, then y.} \)

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