This question involves solving a quadratic equation by factorisation where the roots have different signs.
\( \text{Solve: } x^2 - x - 6 = 0 \)
Choose one option:
Look carefully at the signs. Substitute roots back to verify they satisfy the equation.
Identify two numbers \(m\) and \(n\) such that \(m \times n = -6\) and \(m + n = -1\). Use them to factor the equation as \((x - 3)(x + 2) = 0\).
We use cookies to improve your experience. Read about our Cookie Policy