This Higher-tier problem explores fractional indices and the power-of-a-power rule. It helps you connect square roots with exponents and strengthens understanding of the index laws used in GCSE Maths.
Convert nested powers into one fractional exponent by multiplying exponents. Always simplify before approximating; decimals should only appear in the final step.
At Higher GCSE level, you are expected to interpret and simplify expressions with fractional powers confidently. Fractional indices combine two operations — taking a root and raising to a power. The rule that connects them is \(a^{m/n} = \sqrt[n]{a^m}\). This means you can either raise the number to the power m first and then take the nth root, or take the nth root first and then raise the result to the power m.
When an expression already involves an exponent, such as \((a^p)^q\), the law of indices says you multiply the exponents: \((a^p)^q = a^{p\times q}\). This rule works with all kinds of powers — integers, fractions, and negatives. It makes evaluating nested exponents much easier, since you can rewrite a complicated chain of powers as a single exponent.
Each example uses the same principles: multiply the exponents and then simplify using root notation if needed.
Fractional powers appear throughout science, finance, and computing. In physics, formulas for energy and light intensity use square or cube roots of quantities. In finance, compound interest over fractional years uses fractional exponents. In computer science, algorithms involving time complexity sometimes include powers like \(n^{1/2}\) or \(n^{2/3}\) to express growth rates. Learning to manipulate these exponents prepares you for advanced problem solving beyond GCSE.
Practise converting between roots and fractional powers: \(\sqrt{a} = a^{1/2}\), \(\sqrt[3]{a} = a^{1/3}\), and \(a^{m/n} = (\sqrt[n]{a})^m\). When simplifying nested powers, multiply the exponents first, then evaluate or estimate. Always check your final answer by raising it back to the original power — if it reproduces the base expression, your calculation is correct.