This Higher-tier question introduces negative fractional indices. It combines the laws of indices for powers, roots, and reciprocals — an essential topic for advanced GCSE and A-level preparation.
Handle the negative first by writing the reciprocal, then apply the fractional index rule to simplify. Exact results are preferred over decimals.
Negative fractional indices combine two ideas you already know: fractional powers and negative exponents. Fractional powers link roots and powers through the rule \(a^{m/n} = \sqrt[n]{a^m}\). Negative exponents create reciprocals through \(a^{-k} = \tfrac{1}{a^k}\). When both appear together, they describe the reciprocal of a root or a power, depending on which part of the fraction you focus on.
A negative power does not make a number negative. Instead, it inverts the base. For example, \(2^{-3} = \tfrac{1}{2^3} = \tfrac{1}{8}\). The negative exponent simply tells you to take the reciprocal after applying the positive power. This rule remains true even when the exponent is a fraction: \(a^{-m/n} = \tfrac{1}{a^{m/n}}\).
In every case, the process is the same: turn the negative index into a reciprocal, find the root, then apply the power.
Negative fractional indices appear in many scientific formulas. In physics, inverse-square and inverse-cube laws (such as gravity or sound intensity) use negative powers to represent quantities that decrease with distance. In chemistry, reaction rate equations can involve fractional and negative exponents that express how concentration affects rate. In finance, depreciation and discount factors often use powers less than one, while inverse growth is represented with negative exponents. Learning this rule prepares you to interpret exponential models in many fields.
Always deal with the negative sign first by writing the reciprocal, then apply the fractional power rule. Remember: \(a^{-m/n} = \tfrac{1}{(\sqrt[n]{a})^m}\). Practise with both perfect cubes and fourth powers to become confident in recognising when results simplify to exact fractions. Understanding this concept is essential for simplifying algebraic expressions, solving exponential equations, and interpreting inverse relationships in real-world problems.