This question tests inverse proportion using the constant of proportionality.
This question focuses on a key Higher GCSE Maths skill: using algebra to solve inverse proportion problems. You must recognise the relationship, calculate the constant of proportionality, and then use it to find an unknown value.
If y is inversely proportional to x, this is written as:
y ∝ \frac{1}{x}
which leads to the equation:
y = \frac{k}{x}
Here, k is the constant of proportionality. This constant links all valid pairs of x and y values.
In inverse proportion, x and y change, but their product remains constant:
x × y = k
Once you have found k, you can calculate y for any value of x.
This structured method is exactly what examiners expect to see in Higher-tier answers.
Example: y is inversely proportional to x. When x = 6, y = 20. Find y when x = 10.
The product x × y stays constant at 120.
Example: y is inversely proportional to x. When x = 9, y = 8. Find y when x = 3.
Inverse proportion often appears in GCSE Higher exams combined with algebra, rearranging formulas, or multi-step reasoning. Confidence with constants allows you to solve these questions quickly and accurately.
Always find the constant k first. Once you have it, the rest of the problem becomes straightforward.
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