Exam Questions — Probability
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3 marks
Foundation
Edexcel
Probability
\begin{aligned} &\text{A bag contains 14 buttons.}\\ &5\text{ are black, }4\text{ are white, }5\text{ are grey.}\\ &\text{One button is chosen at random.} \end{aligned}
- i) \[\text{Find the probability of choosing a white button.}\] (1 mark)
- ii) \[\text{Find the probability of not choosing a black button.}\] (1 mark)
- iii) \[\text{Find the probability of choosing a red button.}\] (1 mark)
i)
Answer:
\[\tfrac{4}{14} = \tfrac{2}{7}\]
Solution:
\[\tfrac{4}{14} = \tfrac{2}{7}.\]
ii)
Answer:
\[\tfrac{9}{14}\]
Solution:
\[\tfrac{9}{14}.\]
iii)
Answer:
\[0\]
Solution:
\[\tfrac{0}{14} = 0.\]
3 marks
Foundation
Edexcel
Probability
\begin{aligned} &\text{A box contains 21 crayons.}\\ &7\text{ are red, }9\text{ are blue, }5\text{ are green.}\\ &\text{One crayon is chosen at random.} \end{aligned}
- i) \[\text{Write down the probability of choosing a green crayon.}\] (1 mark)
- ii) \[\text{Write down the probability of not choosing a blue crayon.}\] (1 mark)
- iii) \[\text{Write down the probability of choosing a yellow crayon.}\] (1 mark)
i)
Answer:
\[\tfrac{5}{21}\]
Solution:
\[\tfrac{5}{21}.\]
ii)
Answer:
\[\tfrac{12}{21} = \tfrac{4}{7}\]
Solution:
\[\tfrac{12}{21} = \tfrac{4}{7}.\]
iii)
Answer:
\[0\]
Solution:
\[\tfrac{0}{21} = 0.\]
3 marks
Foundation
Edexcel
Probability
\begin{aligned} &\text{A box has 18 pencils.}\\ &7\text{ are red, }6\text{ are blue, }5\text{ are black.}\\ &\text{One pencil is chosen at random.} \end{aligned}
- i) \[\text{Write down the probability of choosing a red pencil.}\] (1 mark)
- ii) \[\text{Write down the probability of not choosing a blue pencil.}\] (1 mark)
- iii) \[\text{Write down the probability of choosing a green pencil.}\] (1 mark)
i)
Answer:
\[\tfrac{7}{18}\]
Solution:
\[\tfrac{7}{18}.\]
ii)
Answer:
\[\tfrac{12}{18} = \tfrac{2}{3}\]
Solution:
\[\tfrac{12}{18} = \tfrac{2}{3}.\]
iii)
Answer:
\[0\]
Solution:
\[\tfrac{0}{18} = 0.\]
3 marks
Foundation
Edexcel
Probability
\begin{aligned} &\text{A bag has 30 marbles.}\\ &12\text{ are red, }10\text{ are blue, }8\text{ are green.}\\ &\text{One marble is chosen at random.} \end{aligned}
- i) \[\text{Find the probability of choosing a green marble.}\] (1 mark)
- ii) \[\text{Find the probability of not choosing a blue marble.}\] (1 mark)
- iii) \[\text{Find the probability of choosing a yellow marble.}\] (1 mark)
i)
Answer:
\[\tfrac{8}{30} = \tfrac{4}{15}\]
Solution:
\[\tfrac{8}{30} = \tfrac{4}{15}.\]
ii)
Answer:
\[\tfrac{20}{30} = \tfrac{2}{3}\]
Solution:
\[\tfrac{20}{30} = \tfrac{2}{3}.\]
iii)
Answer:
\[0\]
Solution:
\[\tfrac{0}{30} = 0.\]
3 marks
Foundation
Edexcel
Probability
\begin{aligned} &\text{A jar contains 24 beads.}\\ &6\text{ are blue, }10\text{ are red, }8\text{ are green.}\\ &\text{One bead is taken at random.} \end{aligned}
- i) \[\text{Find the probability of choosing a blue bead.}\] (1 mark)
- ii) \[\text{Find the probability of not choosing a red bead.}\] (1 mark)
- iii) \[\text{Find the probability of choosing a yellow bead.}\] (1 mark)
i)
Answer:
\[\tfrac{6}{24} = \tfrac{1}{4}\]
Solution:
\[\tfrac{6}{24} = \tfrac{1}{4}.\]
ii)
Answer:
\[\tfrac{14}{24} = \tfrac{7}{12}\]
Solution:
\[\tfrac{14}{24} = \tfrac{7}{12}.\]
iii)
Answer:
\[0\]
Solution:
\[\tfrac{0}{24} = 0.\]
3 marks
Foundation
Edexcel
Probability
\begin{aligned} &\text{A jar contains 40 sweets.}\\ &15\text{ are strawberry, }12\text{ are orange, }13\text{ are lemon.}\\ &\text{One sweet is chosen at random.} \end{aligned}
- i) \[\text{Find the probability of choosing a lemon sweet.}\] (1 mark)
- ii) \[\text{Find the probability of not choosing a strawberry sweet.}\] (1 mark)
- iii) \[\text{Find the probability of choosing a chocolate sweet.}\] (1 mark)
i)
Answer:
\[\tfrac{13}{40}\]
Solution:
\[\tfrac{13}{40}.\]
ii)
Answer:
\[\tfrac{25}{40} = \tfrac{5}{8}\]
Solution:
\[\tfrac{25}{40} = \tfrac{5}{8}.\]
iii)
Answer:
\[0\]
Solution:
\[\tfrac{0}{40} = 0.\]
3 marks
Foundation
Edexcel
Probability
\begin{aligned} &\text{A bag has 16 counters.}\\ &4\text{ are yellow, }5\text{ are blue, }7\text{ are red.}\\ &\text{One counter is chosen at random.} \end{aligned}
- i) \[\text{Find the probability of choosing a red counter.}\] (1 mark)
- ii) \[\text{Find the probability of not choosing a yellow counter.}\] (1 mark)
- iii) \[\text{Find the probability of choosing a green counter.}\] (1 mark)
i)
Answer:
\[\tfrac{7}{16}\]
Solution:
\[\tfrac{7}{16}.\]
ii)
Answer:
\[\tfrac{12}{16} = \tfrac{3}{4}\]
Solution:
\[\tfrac{12}{16} = \tfrac{3}{4}.\]
iii)
Answer:
\[0\]
Solution:
\[\tfrac{0}{16} = 0.\]
3 marks
Foundation
Edexcel
Probability
\begin{aligned} &\text{A basket has 12 fruits.}\\ &5\text{ are apples, }4\text{ are bananas, }3\text{ are pears.}\\ &\text{One fruit is picked at random.} \end{aligned}
- i) \[\text{Write down the probability of choosing a banana.}\] (1 mark)
- ii) \[\text{Write down the probability of not choosing a pear.}\] (1 mark)
- iii) \[\text{Write down the probability of choosing an orange.}\] (1 mark)
i)
Answer:
\[\tfrac{4}{12} = \tfrac{1}{3}\]
Solution:
\[\tfrac{4}{12} = \tfrac{1}{3}.\]
ii)
Answer:
\[\tfrac{9}{12} = \tfrac{3}{4}\]
Solution:
\[\tfrac{9}{12} = \tfrac{3}{4}.\]
iii)
Answer:
\[0\]
Solution:
\[\tfrac{0}{12} = 0.\]
3 marks
Foundation
Edexcel
Probability
\begin{aligned} &\text{A box has 25 balls.}\\ &10\text{ are white, }7\text{ are black, }8\text{ are red.}\\ &\text{One ball is taken at random.} \end{aligned}
- i) \[\text{Find the probability of taking a black ball.}\] (1 mark)
- ii) \[\text{Find the probability of not taking a red ball.}\] (1 mark)
- iii) \[\text{Find the probability of taking a green ball.}\] (1 mark)
i)
Answer:
\[\tfrac{7}{25}\]
Solution:
\[\tfrac{7}{25}.\]
ii)
Answer:
\[\tfrac{17}{25}\]
Solution:
\[\tfrac{17}{25}.\]
iii)
Answer:
\[0\]
Solution:
\[\tfrac{0}{25} = 0.\]
3 marks
Foundation
Edexcel
Probability
\begin{aligned} &\text{A bag contains 20 counters.}\\ &6\text{ are blue, }8\text{ are red, }6\text{ are green.}\\ &\text{One counter is chosen at random.} \end{aligned}
- i) \[\text{Write down the probability of choosing a red counter.}\] (1 mark)
- ii) \[\text{Write down the probability of not choosing a blue counter.}\] (1 mark)
- iii) \[\text{Write down the probability of choosing a yellow counter.}\] (1 mark)
i)
Answer:
\[\tfrac{8}{20} = \tfrac{2}{5}\]
Solution:
\[\tfrac{8}{20} = \tfrac{2}{5}.\]
ii)
Answer:
\[\tfrac{14}{20} = \tfrac{7}{10}\]
Solution:
\[\tfrac{20-6}{20} = \tfrac{14}{20} = \tfrac{7}{10}.\]
iii)
Answer:
\[0\]
Solution:
\[\tfrac{0}{20} = 0.\]