Surface Area of a Cylinder

\( S=2\pi r h+2\pi r^2 \)
Geometry GCSE

\( Cylinder with r=5 cm, h=7 cm. Find S. \)

Hint (H)
Work out CSA and ends separately.

Explanation

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Statement

The surface area of a cylinder is the total area of its curved surface plus the area of its two circular ends. A cylinder has two key measurements: the radius \(r\) of the circular base and the height \(h\) of the curved side. The formula for the total surface area is:

\[ S = 2\pi r h + 2\pi r^2 \]

The first term \(2\pi r h\) gives the curved surface area (the “label” wrapped around the cylinder), while the second term \(2\pi r^2\) gives the combined area of the two circular ends (top and bottom).

Why it’s true

  • The cylinder’s side can be “unwrapped” into a rectangle with width equal to the circumference of the circle (\(2\pi r\)) and height equal to the cylinder’s height (\(h\)). So its area is \(2\pi r h\).
  • Each end is a circle of radius \(r\), area \(\pi r^2\). There are two ends, so their total area is \(2\pi r^2\).
  • Adding these together gives the formula: \(S = 2\pi r h + 2\pi r^2\).

Recipe (how to use it)

  1. Identify the radius \(r\) and the height \(h\).
  2. Calculate the curved surface area: \(2\pi r h\).
  3. Calculate the area of the two circles: \(2\pi r^2\).
  4. Add them together for the total surface area.
  5. Give the final answer in square units (cm², m², etc.).

Spotting it

Use this formula whenever the problem involves a cylinder and asks for its total surface area (e.g., tins, pipes, tubes). If only the curved part is needed (like labelling a can), use \(2\pi r h\) alone.

Common pairings

  • Volume of a cylinder: \(V = \pi r^2 h\).
  • Area of a circle: \(A = \pi r^2\).

Mini examples

  1. Given: \(r=3\), \(h=10\). Find: \(S\). Answer: \(2\pi \times 3 \times 10 + 2\pi \times 9 = 60\pi + 18\pi = 78\pi \approx 245.0\).
  2. Given: \(r=5\), \(h=7\). Find: \(S\). Answer: \(2\pi \times 5 \times 7 + 2\pi \times 25 = 70\pi + 50\pi = 120\pi \approx 376.99\).

Pitfalls

  • Forgetting to include the circular ends when asked for total surface area.
  • Mixing up diameter and radius.
  • Leaving the answer without square units.

Exam strategy

  • Write each step separately to avoid dropping a term.
  • If an exact form is required, leave your answer in terms of \(\pi\).
  • If a decimal is required, use a calculator and round to 1 or 2 decimal places depending on the question.

Summary

The surface area of a cylinder includes both the curved surface and the circular ends. Always check whether the question wants the total surface area or just the curved part. Use the formula \(S = 2\pi r h + 2\pi r^2\), keep track of units, and decide whether to give your answer in exact terms or as a rounded decimal.

Worked examples

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  1. \( Find the surface area of a cylinder with r=3 cm, h=10 cm. Leave your answer in terms of pi. \)
    1. \( CSA=2πrh=2π×3×10=60π \)
    2. \( Ends=2πr²=2π×9=18π \)
    3. \( Total=78π \)
    Answer: 78\pi
  2. \( A cylinder has r=5 cm, h=7 cm. Find its surface area. \)
    1. \( CSA=2π×5×7=70π \)
    2. \( Ends=2π×25=50π \)
    3. \( Total=120π≈376.99 \)
    Answer: \( 376.99\,cm^2 \)
  3. \( Find surface area for r=4 cm, h=12 cm. \)
    1. \( CSA=2π×4×12=96π \)
    2. \( Ends=2π×16=32π \)
    3. \( Total=128π≈402.12 \)
    Answer: \( 402.12\,cm^2 \)
  4. \( Cylinder with r=6 cm, h=8 cm. Find S. \)
    1. \( CSA=2π×6×8=96π \)
    2. \( Ends=2π×36=72π \)
    3. \( Total=168π≈527.79 \)
    Answer: \( 527.79\,cm^2 \)
  5. \( A cylindrical can has r=7 cm, h=10 cm. Find total surface area. \)
    1. \( CSA=2π×7×10=140π \)
    2. \( Ends=2π×49=98π \)
    3. \( Total=238π≈747.70 \)
    Answer: \( 747.70\,cm^2 \)
  6. \( Cylinder with r=12 cm, h=20 cm. Find S. \)
    1. \( CSA=2π×12×20=480π \)
    2. \( Ends=2π×144=288π \)
    3. \( Total=768π≈2413.72 \)
    Answer: \( 2413.72\,cm^2 \)
  7. \( Find surface area for cylinder with r=15 cm, h=10 cm. \)
    1. \( CSA=2π×15×10=300π \)
    2. \( Ends=2π×225=450π \)
    3. \( Total=750π≈2356.19 \)
    Answer: \( 2356.19\,cm^2 \)
  8. A water pipe has radius 8 cm and height 30 cm. Find total surface area.
    1. \( CSA=2π×8×30=480π \)
    2. \( Ends=2π×64=128π \)
    3. \( Total=608π≈1909.86 \)
    Answer: \( 1909.86\,cm^2 \)
  9. \( Calculate S for r=20 cm, h=25 cm. \)
    1. \( CSA=2π×20×25=1000π \)
    2. \( Ends=2π×400=800π \)
    3. \( Total=1800π≈5654.87 \)
    Answer: \( 5654.87\,cm^2 \)
  10. \( Cylinder with r=25 cm, h=40 cm. Find total surface area. \)
    1. \( CSA=2π×25×40=2000π \)
    2. \( Ends=2π×625=1250π \)
    3. \( Total=3250π≈10210.18 \)
    Answer: \( 10210.18\,cm^2 \)