Surface Area of a Cone
\( S=\pi r\,\ell+\pi r^2 \)
Geometry
GCSE
∑ π √ ≈
\( A cone has r = 6 cm and vertical height h = 8 cm. Find the total surface area (in terms of π). \)
Explanation
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Statement
The surface area of a cone is the sum of the curved (lateral) surface area and the base area:
\[
S = \pi r \ell + \pi r^2
\]
where \(r\) is the radius and \(\ell\) is the slant height of the cone.
Why it’s true
- The curved surface of a cone unfolds into a sector of a circle with radius \(\ell\). Its area is \(\pi r \ell\).
- The circular base has area \(\pi r^2\).
- Adding them gives the total surface area.
Recipe (how to use it)
- Identify the radius \(r\) and slant height \(\ell\).
- Calculate the curved surface area using \(\pi r \ell\).
- Calculate the base area using \(\pi r^2\).
- Add the two areas to get the total surface area.
Spotting it
Look for words like “surface area of a cone”, “total surface area”, or a problem giving radius and slant height.
Common pairings
- Volume of a cone \(\tfrac{1}{3}\pi r^2 h\).
- Pythagoras’ theorem if slant height is not given (\(\ell = \sqrt{r^2 + h^2}\)).
Mini examples
- Given: \(r=3\), \(\ell=5\). Answer: \(S=\pi(3)(5)+\pi(3^2)=15\pi+9\pi=24\pi\).
- Given: \(r=7\), \(\ell=25\). Answer: \(S=\pi(7)(25)+\pi(49)=175\pi+49\pi=224\pi\).
Pitfalls
- Confusing slant height with vertical height.
- Forgetting to include the base area.
- Mixing units (e.g. cm with m).
Exam strategy
- Check whether the question asks for curved surface area only or total surface area.
- Write down both terms clearly before adding.
- Always square the radius only when calculating \(\pi r^2\).
Summary
The surface area of a cone is found with \(S = \pi r \ell + \pi r^2\). The first term is the curved surface, the second is the base area.
Worked examples
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Find the surface area of a cone with radius 3 cm and slant height 5 cm (leave in terms of π).
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\( S = πrℓ + πr² \)
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\( S = π(3)(5) + π(3²) \)
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\( S = 15π + 9π = 24π \)
Answer:
24π cm²
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\( Find the surface area of a cone with r=4 cm, ℓ=6 cm. \)
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\( S = πrℓ + πr² \)
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\( S = π(4)(6) + π(16) \)
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\( S = 24π + 16π = 40π \)
Answer:
40π cm²
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\( Find the total surface area when r=7 cm, ℓ=25 cm. \)
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\( S = π(7)(25) + π(49) \)
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\( S = 175π + 49π = 224π \)
Answer:
224π cm²
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\( A cone has r=10 cm, ℓ=15 cm. Find surface area. \)
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\( S = π(10)(15) + π(100) \)
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\( S = 150π + 100π = 250π \)
Answer:
250π cm²
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\( Find the surface area for r=2 cm, ℓ=5 cm. \)
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\( S = π(2)(5) + π(4) \)
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\( S = 10π + 4π = 14π \)
Answer:
14π cm²
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\( A cone has r=6 cm and vertical height h=8 cm. Find surface area. \)
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\( Find ℓ = √(r²+h²) = √(36+64)=√100=10 \)
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\( S = π(6)(10) + π(36) \)
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\( S = 60π + 36π = 96π \)
Answer:
96π cm²
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\( Find surface area of a cone with r=9 cm, h=12 cm. \)
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\( ℓ=√(81+144)=√225=15 \)
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\( S=π(9)(15)+π(81) \)
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\( S=135π+81π=216π \)
Answer:
216π cm²
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\( A cone with r=8 cm, ℓ=17 cm. Find surface area. \)
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\( S = π(8)(17) + π(64) \)
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\( S = 136π + 64π = 200π \)
Answer:
200π cm²
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\( Find total surface area when r=5 cm, ℓ=13 cm. \)
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\( S=π(5)(13)+π(25) \)
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\( S=65π+25π=90π \)
Answer:
90π cm²
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\( Find surface area of cone with r=12 cm, ℓ=20 cm. \)
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\( S=π(12)(20)+π(144) \)
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\( S=240π+144π=384π \)
Answer:
384π cm²