Simple Interest

\( I=\tfrac{P r t}{100},\qquad A=P+I \)
Percentages GCSE
Question 11 of 20

Find the simple interest on £5400 at 11% for 3 years.

Tips: use ^ for powers, sqrt() for roots, and type pi for π.
Hint (H)
\( Use I=(Prt)/100 \)

Explanation

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Statement

For simple interest calculations:

\[ I = \frac{Prt}{100}, \quad A = P+I \]

where \(P\) is the principal, \(r\) is the annual rate of interest (%), \(t\) is the time in years, \(I\) is interest, and \(A\) is the final amount.

Why it’s true

  • Simple interest grows linearly — the same amount is added each year.
  • For one year: interest = \(P \times r/100\).
  • For \(t\) years: interest = \(P \times r/100 \times t\).
  • Total = principal + interest.

Recipe (how to use it)

  1. Identify \(P\), \(r\), and \(t\).
  2. Calculate \(I=(Prt)/100\).
  3. Add to principal for total \(A=P+I\).

Spotting it

Look for problems with fixed yearly percentages, e.g. “£500 at 6% simple interest for 3 years”.

Common pairings

  • Bank savings questions.
  • Loans and repayments.
  • Comparisons with compound interest.

Mini examples

  1. £500 at 6% for 3 years → \(I=(500×6×3)/100=90\), \(A=590\).
  2. £2000 at 4% for 5 years → \(I=(2000×4×5)/100=400\), \(A=2400\).
  3. £800 at 10% for 2 years → \(I=(800×10×2)/100=160\), \(A=960\).

Pitfalls

  • Forgetting to divide by 100 when rate is a percentage.
  • Using compound instead of simple interest formula.
  • Confusing years with months (convert months into years).

Exam strategy

  • Write down values of \(P,r,t\) before calculating.
  • Always check if question asks for interest or total amount.
  • If given monthly/quarterly, convert time into years correctly.

Summary

Simple interest: \(I=(Prt)/100\), \(A=P+I\). Interest increases in a straight line with time.

Worked examples

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  1. Find the simple interest on £500 at 6% for 3 years.
    1. \( I=(500×6×3)/100=90 \)
    2. \( A=500+90=590 \)
    Answer: \( I=£90, A=£590 \)
  2. Calculate interest on £2000 at 4% for 5 years.
    1. \( I=(2000×4×5)/100=400 \)
    2. \( A=2400 \)
    Answer: \( I=£400, A=£2400 \)
  3. Find the simple interest on £800 at 10% for 2 years.
    1. \( I=(800×10×2)/100=160 \)
    2. \( A=960 \)
    Answer: \( I=£160, A=£960 \)
  4. £1500 is invested at 5% simple interest for 4 years. Find the interest.
    1. \( I=(1500×5×4)/100=300 \)
    Answer: £300
  5. How much in total is repaid for a loan of £1200 at 12% simple interest for 1 year?
    1. \( I=(1200×12×1)/100=144 \)
    2. \( A=1344 \)
    Answer: £1344
  6. £750 is borrowed at 8% for 3 years. Find the interest.
    1. \( I=(750×8×3)/100=180 \)
    Answer: £180
  7. £3000 at 3% simple interest for 7 years. Find the total amount.
    1. \( I=(3000×3×7)/100=630 \)
    2. \( A=3630 \)
    Answer: £3630
  8. Find the simple interest on £4500 at 9% for 2 years.
    1. \( I=(4500×9×2)/100=810 \)
    Answer: £810
  9. A loan of £2500 at 6% simple interest for 5 years. Find the interest and total.
    1. \( I=(2500×6×5)/100=750 \)
    2. \( A=3250 \)
    Answer: \( I=£750, A=£3250 \)
  10. £1800 invested at 7% for 4 years. Find the final amount.
    1. \( I=(1800×7×4)/100=504 \)
    2. \( A=2304 \)
    Answer: £2304