Geometric Sequence (n-th Term)

\( u_n = ar^{\,n-1} \)
Algebra GCSE

\( A geometric sequence has a=1 and r=-1/2. Which is u_5? \)

Hint (H)
\( Use u_n=ar^{n-1}. \)

Explanation

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Statement

A geometric sequence is a list of numbers where each term is obtained by multiplying the previous term by a fixed constant called the common ratio. If the first term is \(a\) and the common ratio is \(r\), then the \(n\)-th term is

\[ u_n = ar^{\,n-1}. \]

Why it works

  • The first few terms are \(u_1=a,\; u_2=ar,\; u_3=ar^2,\; u_4=ar^3,\ldots\)
  • We can see the pattern: to reach the \(n\)-th term we have multiplied by \(r\) exactly \(n-1\) times, so \(u_n=ar^{n-1}\).
  • When \(|r|>1\) the terms grow in magnitude (exponential growth). When \(|r|<1\) they shrink towards 0 (exponential decay). If \(r<0\) the terms alternate signs.

Recipe (Steps to Apply)

  1. Identify the first term \(a\) (usually the first number listed).
  2. Find the common ratio \(r\) by dividing a term by the one before it: \(r=\dfrac{u_{k+1}}{u_k}\) (for any consecutive pair).
  3. Substitute into \(u_n = ar^{n-1}\) to find any term.
  4. To find a particular position \(n\) for a known value, set \(u_n\) equal to that value and solve \(ar^{n-1}= \text{value}\) (often by recognising powers or using logs if needed).

Spotting it

Look for a constant multiplicative change between consecutive terms (e.g., ×2 each time, or ×0.5 each time). That is geometric, not arithmetic (which uses constant addition).

Common pairings

  • Sum of first \(n\) terms of a geometric series.
  • Exponential growth/decay models (interest, population, depreciation).
  • Indices and powers rules.

Mini examples

  1. Sequence: \(3, 6, 12, 24, \ldots\) → \(a=3, r=2\). Then \(u_5=3\cdot 2^{4}=48\).
  2. Sequence: \(80, 40, 20, 10, \ldots\) → \(a=80, r=\tfrac12\). Then \(u_n=80\left(\tfrac12\right)^{n-1}\).

Pitfalls

  • Mixing up geometric with arithmetic sequences. Check by dividing, not subtracting.
  • Forgetting the exponent is \(n-1\), not \(n\).
  • Sign errors when \(r\) is negative (terms alternate signs).

Exam Strategy

  • Always write \(a\) and \(r\) clearly before substituting into \(u_n=ar^{n-1}\).
  • For “find \(n\)” questions, try to recognise powers first (e.g., \(2^k, 3^k, 10^k\)).
  • Check reasonableness: with \(0<r<1\) terms should decrease; with \(r>1\) they should increase.

Worked Micro Example

Given the geometric sequence \(5, 10, 20, 40, \ldots\). Find the 7th term.

Here \(a=5,\; r=2\). So \(u_7=5\cdot 2^{6}=5\cdot 64=320.\)

Summary

The n-th term of a geometric sequence with first term \(a\) and common ratio \(r\) is \(u_n=ar^{n-1}\). Use it to compute terms, identify the formula from data, and compare growth/decay behaviours.

Worked examples

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  1. \( For the geometric sequence 3, 6, 12, 24, ... find u_6. \)
    1. \( a=3, r=2 \)
    2. \( u_6 = 3 * 2^(5) = 3 * 32 = 96 \)
    Answer: 96
  2. \( A geometric sequence has a=5 and r=3. Find u_4. \)
    1. \( u_4 = 5 * 3^(3) = 5 * 27 = 135 \)
    Answer: 135
  3. \( Given sequence 80, 40, 20, 10, ... write u_n. \)
    1. \( a=80, r=1/2 \)
    2. \( u_n = 80*(1/2)^(n-1) \)
    Answer: \( u_n = 80*(1/2)^(n-1) \)
  4. \( Sequence: 9, 3, 1, 1/3, ... Find a and r, then u_7. \)
    1. \( a=9 \)
    2. \( r=3/9=1/3 \)
    3. \( u_7 = 9*(1/3)^(6) = 9/729 = 1/81 \)
    Answer: 1/81
  5. \( In a geometric sequence, a=2 and u_5=162. Find r. \)
    1. \( u_5 = a r^(4) = 2 r^4 = 162 \)
    2. \( r^4 = 81 => r = 3 (take positive ratio from context) \)
    Answer: 3
  6. \( The sequence has u_1=7 and u_3=63. Find r and u_n. \)
    1. \( u_3 = 7 r^2 = 63 => r^2 = 9 => r = 3 or r = -3 \)
    2. \( Assuming positive ratio: r=3 \)
    3. \( u_n = 7*3^(n-1) \)
    Answer: \( u_n = 7*3^(n-1) \)
  7. \( Find n if a=4, r=2 and u_n=128. \)
    1. \( 4*2^(n-1)=128 \)
    2. \( 2^(n-1)=32=2^5 \)
    3. \( n-1=5 => n=6 \)
    Answer: 6
  8. \( A geometric sequence: -5, 10, -20, 40, ... Find u_n. \)
    1. \( a=-5 \)
    2. \( r=10/(-5)=-2 \)
    3. \( u_n = -5*(-2)^(n-1) \)
    Answer: \( u_n = -5*(-2)^(n-1) \)
  9. \( Given u_2=12 and u_5=96 for a geometric sequence, find a and r. \)
    1. \( u_2=ar=12 \)
    2. \( u_5=ar^4=96 \)
    3. \( Divide: (ar^4)/(ar)=r^3=8 => r=2 \)
    4. \( Then a=12/r=6 \)
    Answer: \( a=6, r=2 \)
  10. \( A sequence halves each time and starts at 640. Find u_7. \)
    1. \( a=640, r=1/2 \)
    2. \( u_7=640*(1/2)^6=640/64=10 \)
    Answer: 10