Statement
A quadratic expression of the form:
\[
x^2 + bx + c
\]
can be factorised into two brackets:
\[
x^2 + bx + c = (x+p)(x+q)
\]
where the numbers \(p\) and \(q\) satisfy the conditions:
- \(p + q = b\)
- \(p \times q = c\)
Why it works
- Expanding \((x+p)(x+q)\) gives \(x^2 + (p+q)x + pq\).
- This matches the original quadratic \(x^2 + bx + c\) when \(p+q = b\) and \(pq = c\).
- Therefore, finding the correct pair of numbers \(p, q\) allows us to factorise the quadratic into brackets.
Recipe (Steps to Factorise)
- Write down the quadratic \(x^2 + bx + c\).
- Find two numbers \(p, q\) such that:
- \(p+q = b\)
- \(p \times q = c\)
- Write the factorised form as \((x+p)(x+q)\).
- Check by expanding to confirm it matches the original quadratic.
Spotting it
Use this method when the coefficient of \(x^2\) is 1 (monic quadratics). If the coefficient is not 1, you need other methods such as grouping or the quadratic formula.
Common pairings
- Solving quadratic equations (\(x^2 + bx + c = 0\)).
- Sketching quadratic graphs (roots come from the factors).
- Simplifying algebraic fractions.
Mini examples
- \(x^2 + 5x + 6 = (x+2)(x+3)\), since 2+3=5 and 2×3=6.
- \(x^2 - x - 6 = (x-3)(x+2)\), since -3+2=-1 and -3×2=-6.
Pitfalls
- Forgetting that signs matter (both addition and multiplication conditions must hold).
- Mixing up the order — although \((x+p)(x+q)\) = \((x+q)(x+p)\).
- Trying to factorise quadratics with no integer factors (these need quadratic formula or completing the square).
Exam Strategy
- Write down factor pairs of \(c\) to test possible values quickly.
- Check sum = \(b\), product = \(c\).
- Expand your final brackets to verify correctness.
Worked Micro Example
Factorise \(x^2 + 7x + 10\).
We need two numbers that multiply to 10 and add to 7: \(5\) and \(2\).
So, \(x^2 + 7x + 10 = (x+5)(x+2)\).
Summary
To factorise \(x^2 + bx + c\), find two numbers whose product is \(c\) and sum is \(b\). This quick method works for monic quadratics and is essential for solving quadratic equations and simplifying algebraic expressions.