\( \begin{aligned}
&\text{To reverse a bearing, add or subtract } 180^{\circ} \text{ so the result is between } 0^{\circ} \text{ and } 360^{\circ}.
\end{aligned} \)
Question 6:
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\[ \begin{array}{l}
\text{The bearing of point Q from point P is } 62^{\circ}. \\
\text{Work out the bearing of point P from point Q.}
\end{array} \]
Answer:\(242^{\circ}\)
Explanation:
\begin{aligned}
&\text{Bearings are measured clockwise from north.} \\
&\text{The reverse bearing differs by } 180^{\circ}. \\
&62^{\circ} + 180^{\circ} = 242^{\circ}. \\
&\text{So the bearing of point P from Q is } 242^{\circ}.
\end{aligned}