Inverse Proportion

Inverse proportion describes a relationship where one quantity increases while the other decreases. It is the opposite of direct proportion and is based on ideas from ratio, with relationships often written in the form y = k/x.

Overview

Two quantities are in inverse proportion when one increases and the other decreases so that their product remains constant.

\( y \propto \frac{1}{x} \quad \text{and} \quad y = \frac{k}{x} \)
\( xy = k \)

Inverse proportion often appears in problems involving time, speed, workers, pipes, area and pressure.

What you should understand after this topic

  • Understand what inverse proportion means
  • Understand how inverse proportion differs from direct proportion
  • Use y = k/x to solve problems
  • Use xy = k to solve problems
  • Solve missing-value problems involving inverse proportion

Key Definitions

Inverse Proportion

When one quantity increases while the other decreases so that the product stays constant.

Inverse Proportional To

\( y \propto \frac{1}{x} \)

Constant of Proportionality

The fixed value \( k \) in \( y = \frac{k}{x} \) or \( xy = k \).

Product

The result of multiplying two values together.

Reciprocal Relationship

One quantity is proportional to the reciprocal of the other.

Inverse Graph Shape

The graph is a curve, not a straight line.

Key Rules

Multiply to find the constant

\( k = xy \)

Use inverse formula

\( y = \frac{k}{x} \)

One goes up, the other goes down

That is the key pattern.

Graph is not a straight line

Inverse proportion makes a curve.

Quick Recognition

Words

“is inversely proportional to”

Equation

\( y = \frac{12}{x} \)

Product check

If \( xy \) stays constant, it is inverse proportion.

Graph pattern

A decreasing curve, not a straight line.

How to Solve

Step 1: Recognise inverse proportion

In inverse proportion, as one value increases, the other decreases so that their product stays constant. It is useful to compare this with direct proportion.

\( y \propto \frac{1}{x} \)
Exam thinking: If one doubles and the other halves, it is inverse proportion.

Step 2: Write the equation

Convert the proportional relationship into an equation.

\( y = \frac{k}{x} \)
\( xy = k \)
Both forms are equivalent and can be used in calculations.

Step 3: Find the constant \(k\)

Use given values to calculate \(k\).

If \( x = 4, y = 6 \):
\( k = xy = 4 \times 6 = 24 \)
Exam tip: Multiply the pair of values to find \(k\).

Step 4: Use the equation

Substitute new values into the equation.

\( y = \frac{24}{x} \)
If \( x = 8 \): \( y = 3 \)

Step 5: Graph of inverse proportion

The graph is a curve that gets closer to the axes but never touches them.

Exam tip: Inverse proportion graphs never cross the axes.

Key idea

The graph is not a straight line and has two branches.

Inverse proportion graph showing a decreasing curve where x increases and y decreases while xy stays constant

Step 6: How to recognise inverse proportion

See direct proportion for comparison.

From words

Look for 'inversely proportional'.

From a table

Check if \( xy \) is constant.

From an equation

Looks like \( y = \frac{k}{x} \).

From context

More workers → less time, higher speed → less time.

Step 7: Exam method summary

  1. Recognise inverse proportion.
  2. Write \( y = \frac{k}{x} \).
  3. Find \(k\) using known values.
  4. Substitute to find the answer.

Example Questions

Edexcel

Exam-style questions inspired by Edexcel GCSE Mathematics, focusing on recognising and solving problems involving inverse proportion.

Edexcel

State whether \( y \) is inversely proportional to \( x \) in the equation \( y = \frac{6}{x} \).

Edexcel

Given that \( y \propto \frac{1}{x} \) and \( y = 4 \) when \( x = 3 \), find \( y \) when \( x = 6 \).

Edexcel

Given that \( y \) is inversely proportional to \( x \), and \( y = 10 \) when \( x = 2 \), find the constant of proportionality.

Edexcel

The time taken to complete a journey is inversely proportional to the speed. If a journey takes 5 hours at 60 km/h, how long will it take at 100 km/h?

Edexcel

Write the relationship \( y \propto \frac{1}{x} \) as an equation using a constant of proportionality.

AQA

Exam-style questions based on the AQA GCSE Mathematics specification, focusing on forming and solving equations involving inverse proportion.

AQA

Given that \( y \propto \frac{1}{x} \) and \( y = 8 \) when \( x = 5 \), find an equation connecting \( y \) and \( x \).

AQA

If \( y \) is inversely proportional to \( x \), and \( y = 12 \) when \( x = 4 \), find \( x \) when \( y = 3 \).

AQA

The number of workers needed to complete a job is inversely proportional to the time taken. If 6 workers take 10 days, how many workers are required to complete the job in 4 days?

AQA

The pressure of a gas varies inversely with its volume. If the pressure is 200 kPa when the volume is 5 m^3, find the pressure when the volume is 8 m^3.

AQA

Explain how you recognise an inverse proportion from a table or graph.

OCR

Exam-style questions aligned with OCR GCSE Mathematics, emphasising reasoning, algebraic modelling, and graphical interpretation.

OCR

Given that \( y \propto \frac{1}{x} \), and \( y = 9 \) when \( x = 2 \), find the value of \( y \) when \( x = 6 \).

OCR

Write \( y \propto \frac{1}{x} \) as an equation involving a constant \( k \).

OCR

A fixed distance is travelled at different speeds. If it takes 3 hours at 80 km/h, how long will it take at 120 km/h?

OCR

Two variables are inversely proportional. When \( x = 4 \), \( y = 15 \). Find the value of \( y \) when \( x = 10 \).

OCR

State the key features of a graph that represents inverse proportion.

Exam Checklist

Step 1

If you see “inversely proportional”, write \( y = \frac{k}{x} \).

Step 2

Use known values to find \( k \) by multiplying.

Step 3

Substitute the new value into the completed equation.

Step 4

Check whether the answer makes sense: bigger \( x \), smaller \( y \).

Most common exam mistakes

Wrong formula

Using \( y = kx \) instead of \( y = \frac{k}{x} \).

Wrong constant

Dividing to find \( k \) when you should multiply.

Pattern confusion

Not checking whether the product stays constant.

Reasonableness mistake

Getting a larger answer when the question should produce a smaller one.

Common Mistakes

These are common mistakes students make when working with inverse proportion in GCSE Maths.

Using the wrong formula

Incorrect

A student uses \(y = kx\) instead of \(y = \frac{k}{x}\).

Correct

Inverse proportion follows \(y = \frac{k}{x}\) or \(xy = k\). This is different from direct proportion, which uses \(y = kx\).

Finding k incorrectly

Incorrect

A student divides instead of multiplying to find k.

Correct

For inverse proportion, use \(k = x \times y\), not division. Multiply the values to find the constant.

Relying only on “one goes up, one goes down”

Incorrect

A student assumes inverse proportion just because one value increases and the other decreases.

Correct

Check that the product \(xy\) is constant. This confirms inverse proportion.

Confusing direct and inverse proportion

Incorrect

A student uses the method for direct proportion.

Correct

Direct proportion uses \(y = kx\), while inverse proportion uses \(y = \frac{k}{x}\). Always identify the relationship first.

Expecting a straight-line graph

Incorrect

A student draws a straight line graph.

Correct

Inverse proportion graphs are curves (hyperbolas), not straight lines. They approach the axes but do not touch them.

Try It Yourself

Practise solving problems involving inverse proportional relationships.

Questions coming soon
Foundation

Foundation Practice

Understand inverse proportion and solve simple problems.

Question 1

If more workers are used to do a job, what happens to the time taken?

Games

Practise this topic with interactive games.

Games coming soon.

Frequently Asked Questions